Quick bugdrop

[Chris Marston <nospam@thanx>]

Er, I sent this to rse@engelschall.com, but I'm not sure it got through,
so I joined the list and am resubmitting it. :)

There seems to be a bug in WML2.0.2's <rollover> (at least, so far as
interaction with Netscape is concerned). Essentially, since each dhtml layer
(``absolutely positioned block'', in CSS-speak) is a javascript 'document'
object in its own right, any javascript it contains cannot see the javascript
functions of its peers. This means that javascript errors are thrown 
when code looks like:

<span id=floatingyogi>
<rollover ... >
</span>
<span id=magicbunny>
<rollover ... >
</span>

'magicbunny's rollover will complain that the rollover functions cannot
be found.


Enclosed is a workaround in mp4h/eperl.

#workaround for an annoying rollover bug that causes 
#javascript errors on dhtml netscape docs.

<define-tag span endtag=required>
	<: push @LAYERS, {}; :>
	<span* %attributes >
	%body
	</span*>
	<: pop @LAYERS; :>
</define-tag>

<define-tag div endtag=required>
	<: push @LAYERS, {}; :>
	<div* %attributes >
	%body
	</div*>
	<: pop @LAYERS; :>
</define-tag>

<define-tag layer endtag=required>
	<: push @LAYERS, {}; :>
	<layer* %attributes >
	%body
	</layer*>
	<: pop @LAYERS; :>
</define-tag>

<define-tag cmarstonRollover whitespace=delete>
	<:print q (
<script type="text/javascript" language="JavaScript">
<!-- cmarston@trentu.ca: a quick layering patch

function ro_imgNormal(imgName) {
    if (document.images) {
        document[imgName].src = eval(imgName + "_n.src");
        self.status = '';
    }
}
function ro_imgOver(imgName, descript) {
    if (document.images) {
        document[imgName].src = eval(imgName + "_o.src");
        self.status = descript;
    }
}
--> </script> 
)  unless (  $LAYERS[$#LAYERS]->{'rolled'} || 
	     $LAYERS->{'first'}  );
$LAYERS[$#LAYERS]->{'rolled'} = 1;
$LAYERS->{'first'} = 0;
:>
<rollover %attributes >
</define-tag>


-- 
Civilization advances by extending the number of important operations which we can perform without thinking. (Alfred North Whitehead) 
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